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刘同学2018-03-25 15:37:45

Use the following values from a student's t-distribution to establish a 95% confidence interval for the population mean given a sample size of 10, a sample mean of 6.25, and a sample standard deviation of 12. Assume that the population from which the sample is drawn is normally distributed and the population variance is not known. The 95% confidence interval is closest to a: A Lower bound of –2.33 and an upper bound of 14.83. B Lower bound of –0.71 and an upper bound of 13.21. C Lower bound of –2.20 and an upper bound of 14.70. 这题为什么选2.262这个系数?为什么选这个自由度?

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金程教育顾老师2018-03-26 18:12:29

学员你好,因为总体正态,小样本,用t分布,df=样本量-1=9,查双尾的t分布表,置信度为95%或显著性水平为5%那列,得t值为2.262.

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